(Given) Kb for NH3 is 1.8 × 10−5 Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.
Question: What is the percent of the unprotonated form of ammonia (Kb NH3 = 1.74 x 10-5) in a solution at pH 8.68? What is the percent of the unprotonated form of ammonia ( Kb NH 3 = 1 . 7 4 x 1 0 - 5 ) in a solution at pH
Kb(NH3)=1.8\times 10‒5Give your answer to 2 decimal places Your solution’s ready to go! Enhanced with AI, our expert help has broken down your problem into an easy-to-learn solution you can count on.
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